来源 | 数据分析与统计学之美
x1 = (5 > 3 and 5 < 10)
x1
x2 = (5 > 3 or 5 > 10)
x2
x3 = False
not x3
def func(x):
if x < 18:
print("未成年")
elif x < 30:
print("青年")
else:
print("中老年")
func(25)
def func1(x):
try:
100//x
except:
print("ZeroDivisionError: division by zero(除数不能是0)")
else:
print(f"程序计算结果是{str(100//x)}")
func1(10)
func1(0)
name_list = ["张三","李四","王五"]
for name in name_list:
print(name)
x = 0
while x<9:
print(x)
x += 1
print(9 > 6)
print(6 in [11,6,33])
print(5 is 5)
print(5 == 5)
print(5 == 5 and 7 == 7)
print(5 == 5 or 6 == 7)
print(not(5 == 7))
print(9 < 6)
print(6 in [11,88,33])
print(15 is 5)
print(5 != 5)
print(5 < 5 and 7 == 7)
print(5 <= 3 or 6 >= 7)
print(not(5 == 5))
for i in range(10):
if i <= 5:
continue
print(i)
x = 0
while x < 10:
if x == 5:
break
x += 1
print(x)
def func(x):
try:
100 // x
except:
print("ZeroDivisionError: division by zero(除数不能是0)")
else:
print(f"结果是:{str(100 // x)}")
finally:
print("无论如何,都会执行!")
func(10)
func(0)
x = 15
if x < 18:
raise Exception("不好意思,你的年龄小于18岁,未成年")
import openpyxl
import pandas as pd
from openpyxl import load_workbook()
def func1():
print("关注")
func1()
def func2(x,y):
return x + y
func2(x=2,y=8)
class Person:
name = "张三"
age = 18
p = Person()
p.name,p.age
x = lambda a: a + 8
x(2)
y = lambda a,b: a + b
y(1,1)
z = lambda a,b,c: a * c + b
z(2,5,5)
x = 1
del x
print(x)
x = ["张三","李四","王五"]
del x[0]
print(x)
# 定义一个函数:
def func():
global x
x = "函数中的变量"
# 执行函数:
func()
# x定义在函数中,按说这里打印x会报错,我们看看
print(x)
x = ["张三","李四","王五"]
"张三" in x
# -------------------------
for i in range(3):
print(i)
x = 2.0
y = 2.0
x is y
x == y
x = None
print(x)
if x:
print("嘻嘻")
else:
print("哈哈")
x = 666
assert x == 666
assert x == 888,"x应该等于666,你的输入有误!"
with open("哈哈.txt","r") as f:
print(f.read())
def f():
yield 5
f()
next(f())
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