这是计算今天是今年第几天的代码

#include<stdio.h>

int main()
{
    int year, mon, day, isLeap, i, count;
    int month[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};

printf("输入日期：（输入格式必须为yyyy-mm-dd，如2012-11-24）\n");
    scanf("%d-%d-%d", &year, &mon, &day);

   //判断是否为润年
   if ((year % 400 == 0) || (year % 100 != 0 && year % 4 == 0) )
        isLeap = 1;

   else isLeap = 0;
  
 count = 0;
 month[2] = month[2] + isLeap;
 for (i = 1; i < mon; i++){
      count += month[i];
 }
 count += day;
printf("%d-%d-%d是%d年中的第%d天./n", year, mon, day,year, count);   

return 0;

}