dos获取昨天日期的批处理

@echo off
rem GET YESTERDAY DATE

set dt=%date:~0,10%
rem date format is "YYYY-MM-DD"

rem set /P dt="Input Date: "

set dy=%dt:~0,4%
set dm=%dt:~5,2%
set dd=%dt:~8,2%

if %dm%%dd%==0101 goto L01
if %dm%%dd%==0201 goto L02
if %dm%%dd%==0301 goto L07
if %dm%%dd%==0401 goto L02
if %dm%%dd%==0501 goto L04
if %dm%%dd%==0601 goto L02
if %dm%%dd%==0701 goto L04
if %dm%%dd%==0801 goto L02
if %dm%%dd%==0901 goto L02
if %dm%%dd%==1001 goto L05
if %dm%%dd%==1101 goto L03
if %dm%%dd%==1201 goto L06

if %dd%==02 goto L10
if %dd%==03 goto L10
if %dd%==04 goto L10
if %dd%==05 goto L10
if %dd%==06 goto L10
if %dd%==07 goto L10
if %dd%==08 goto L10
if %dd%==09 goto L10
if %dd%==10 goto L11
set /A dd=dd-1
set dt=%dy%-%dm%-%dd%
goto END
:L10
set /A dd=%dd:~1,1%-1
set dt=%dy%-%dm%-0%dd%
goto END
:L11
set dt=%dy%-%dm%-09
goto END

:L02
set /A dm=%dm:~1,1%-1
set dt=%dy%-0%dm%-31
goto END
:L04
set /A dm=dm-1
set dt=%dy%-0%dm%-30
goto END

:L05
set dt=%dy%-09-30
goto END
:L03
set dt=%dy%-10-31
goto END
:L06
set dt=%dy%-11-30
goto END
:L01
set /A dy=dy-1
set dt=%dy%-12-31
goto END

:L07
set /A "dd=dy%%4"
if not %dd%==0 goto L08
set /A "dd=dy%%100"
if not %dd%==0 goto L09
set /A "dd=dy%%400"
if %dd%==0 goto L09
:L08
set dt=%dy%-02-28
goto END
:L09
set dt=%dy%-02-29
goto END

:END

rem 执行程序部分
echo %dt:~0,4%%dt:~5,2%%dt:~8,2%  %dt:~0,4%%dt:~5,2%%dt:~8,2% 2