5.根据前序和中序得到二叉树代码实现，根据中序和后序得到二叉树代码实现（JavaScript版）

根据前序和中序，使用JavaScript编写代码得到二叉树

<!DOCTYPE html>
<html lang="en">

<head>
    <meta charset="UTF-8">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <title>Document</title>
</head>

<body>
    <script>
        var qian = ["a", "b", "d", "e", "c", "f", "g"];
        var zhong = ["d", "b", "e", "a", "f", "c", "g"];

        function Node(value){
            this.value = value;
            this.left = null;
            this.right = null;
        }

        //通过前序和中序还原二叉树
        function resumeTree(qian, zhong){
            if(qian == null || zhong == null || qian.length == 0 || zhong.length == 0 || qian.length != zhong.length) return null;//qian和zhong数组为null或者长度为0，或者两者长度不相等，直接返回
            var root = new Node(qian[0]);//前序第一个节点是二叉树的根节点
            var index = zhong.indexOf(qian[0]);//找到中序里根节点所在的索引
            var zhongLeft = zhong.slice(0, index);//获取中序的左子树
            var zhongRight = zhong.slice(index + 1, zhong.length);//获取中序的右子树
            var qianLeft = qian.slice(1, index + 1);//获取前序的左子树
            var qianRight = qian.slice(index + 1, qian.length);//获取前序的右子树
            root.left = resumeTree(qianLeft, zhongLeft);//找到节点的左节点
            root.right = resumeTree(qianRight, zhongRight);//找到节点的右节点

            return root;//返回二叉树
        }

        var tree = resumeTree(qian, zhong);//获取二叉树
        console.log(tree.left);//打印左子树
        console.log(tree.right);//打印右子树
    </script>
</body>

</html>

前序和中序的到二叉树.html

根据中序和后续，使用JavaScript编写代码得到二叉树

<!DOCTYPE html>
<html lang="en">

<head>
    <meta charset="UTF-8">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <title>Document</title>
</head>

<body>
    <script>
        
        var hou = ["d", "e", "b", "f", "g", "c", "a"];
        var zhong = ["d", "b", "e", "a", "f", "c", "g"];

        function Node(value){
            this.value = value;
            this.left = null;
            this.right = null;
        }

        //通过后序和中序还原二叉树
        function resumeTree(hou, zhong){
            if(hou == null || zhong == null || hou.length == 0 || hou.length == 0 || hou.length != zhong.length) return null;//hou和zhong数组为null或者长度为0，或者两者长度不相等，直接返回
            var root = new Node(hou[hou.length - 1]);//后序最后一个节点是二叉树的根节点
            var index = zhong.indexOf(hou[hou.length - 1]);//找到中序里根节点所在的索引
            var zhongLeft = zhong.slice(0, index);//获取中序的左子树
            var zhongRight = zhong.slice(index + 1, zhong.length);//获取中序的右子树
            var houLeft = hou.slice(0, index);//获取后序的左子树
            var houRight = hou.slice(index, hou.length - 1);//获取后序的右子树
            root.left = resumeTree(houLeft, zhongLeft);//找到节点的左节点
            root.right = resumeTree(houRight, zhongRight);//找到节点的右节点

            return root;//返回二叉树
        }

        var tree = resumeTree(hou, zhong);//获取二叉树
        console.log(tree.left);//打印左子树
        console.log(tree.right);//打印右子树
    </script>
</body>

</html>

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