RSA/ECB/PKCS1Padding加密

由于近期经常被改犇，我的有些犇犇会使用RSA/ECB/PKCS1Padding加密。我的公钥：

Modulus: 7749508816481769130958656717979283807090064162903164284448125194652436835418455841001455979629062396710853788700110904825475002409879758932825196227887201Public Exponent: 65537

解密代码：（直接拿某谷IDE跑就没问题）

import java.math.BigInteger;import java.nio.charset.StandardCharsets;import java.security.*;import java.security.spec.*;import java.util.Base64;import java.util.Scanner;import javax.crypto.Cipher;public class Main {	public static void main(String[] args) throws Exception {		Scanner sca = new Scanner(System.in);		BigInteger mod = sca.nextBigInteger();		BigInteger expo = sca.nextBigInteger();		String str = sca.next();		sca.close();		RSAPublicKeySpec spec = new RSAPublicKeySpec(mod, expo);		KeyFactory factory = KeyFactory.getInstance("RSA");		PublicKey key = factory.generatePublic(spec);		Cipher cipher = Cipher.getInstance("RSA/ECB/PKCS1Padding");		cipher.init(Cipher.DECRYPT_MODE, key);		byte[] data = cipher.doFinal(Base64.getDecoder().decode(str));		String ret = new String(data, StandardCharsets.UTF_8);		System.out.println(ret);	}}

输入格式：共三行，第一行为Modulus，第二行为Public Exponent，第三行为Base64编码的密文。

输入样例：

774950881648176913095865671797928380709006416290316428444812519465243683541845584100145597962906239671085378870011090482547500240987975893282519622788720165537VQMtiDl6jutupZi6T5ooTUejV02LYoz7fYjFwUNy4L7hmLQFeLzJqPQculd3j3/oHF0/Y9nk5A+nHHtgQ4fu/A==